2x^(2/3)-10x^(1/3)-28=0

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Solution for 2x^(2/3)-10x^(1/3)-28=0 equation: 


x in (-oo:+oo)

2*x^(2/3)-(10*x^(1/3))-28 = 0

2*x^(2/3)-10*x^(1/3)-28 = 0

t_1 = x^(1/3)

2*t_1^2-10*t_1^1-28 = 0

2*t_1^2-10*t_1-28 = 0

DELTA = (-10)^2-(-28*2*4)

DELTA = 324

DELTA > 0

t_1 = (324^(1/2)+10)/(2*2) or t_1 = (10-324^(1/2))/(2*2)

t_1 = 7 or t_1 = -2

t_1 = -2

x^(1/3)+2 = 0

1*x^(1/3) = -2 // : 1

x^(1/3) = -2

( -2 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 7

x^(1/3)-7 = 0

1*x^(1/3) = 7 // : 1

x^(1/3) = 7

x^(1/3) = 7 // ^ 3

x = 343

x = 343

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